(1) O₃ O₂ + O

(2) O₃ + O --> 2O₂

a) Adding together the two steps yields: 2O₃ --> 3O₂

b) The intermediate is O atom since it doesn't appear in the overall reaction

c) For each step:

d) The RDS is step 2 since:

a) step 1 is a simple unimolecular reaction

b) the reverse of step 1 does not involve ozone

e) From the result of part (d) and given that the RDS should resemble the empirical rate law,

f) Employing the steady state approximation for [O] :

g) To eliminate [O] from the rate law of the RDS (step 2), use the pre-equilibrium of step 1: